import com.sun.servicetag.SystemEnvironment;
"os.arch" environment may not give you the correct architecture.
Let's try out.
public class OSArchLies {
public static void main(String[] args) {
// Will say "x86" even on a 64-bit machine using a 32-bit Java runtime
SystemEnvironment env = SystemEnvironment.getSystemEnvironment();
final String envArch = env.getOsArchitecture();
// The os.arch property will also say "x86" on a 64-bit machine using a 32-bit runtime
final String propArch = System.getProperty("os.arch");
System.out.println( "getOsArchitecture() says => " + envArch );
System.out.println( "getProperty() says => " + propArch );
}
}
Environment: Windows 7, 64 bit os, 32 bit JVM
Output:
getOsArchitecture() says => x86
getProperty() says => x86
Try this approach,
public class Windows32Or64bitCheck {
public static void main(String[] args) {
boolean is64bit = false;
System.out.println(System.getProperty("sun.arch.data.model", "?"));
System.out.println(System.getProperty("os.arch")); // Please note, the os.arch property will only give you the architecture of the JRE, not of the underlying os.
System.out.println(System.getenv("ProgramFiles(x86)"));
if (System.getProperty("os.name").contains("Windows")) {
is64bit = (System.getenv("ProgramFiles(x86)") != null);
} else {
is64bit = (System.getProperty("os.arch").indexOf("64") != -1);
}
System.out.println("is64bit: " + is64bit);
}
}
Environment: Windows 7, 64 bit os, 32 bit JVM
Output:
32
x86
C:\Program Files (x86)
is64bit: true
This is the only way which i could find from Java( Using native C, there is a better and accurate way to achieve this)
Using C, please follow below link
Other way I have learned recently, using Windows wmi service calls.
> wmic OS get OSArchitecture
C:\Users\KH1205>wmic OS get OSArchitecture
OSArchitecture
64-bit
Try to run this command programatically using Java Runtime process.
